Hi,

If you just want to create an additional column with a hyperlink based on another column you can use UnboundColumn and converter to create the hyperlink.

First you need a converter:

...
public class Conv : IValueConverter
{
	public object Convert(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture)
	{
		if (value is int && targetType == typeof(Uri))
		{
			return new Uri(string.Format("http://mytestsite/pages.aspx?projectid={0}", value));
		}

		return null;
	}

	public object ConvertBack(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture)
	{
		throw new NotImplementedException();
	}
}

Then add an UnboundColumn:

...
<UserControl.Resources>
        <local:Conv x:Key="Conv" />
    </UserControl.Resources>
...
<ig:XamGrid.Columns>
	<ig:TextColumn Key="Id" />
	<ig:UnboundColumn Key="MyUnboundColumnWithHyperlink">
		<ig:UnboundColumn.ItemTemplate>
			<DataTemplate>
				<HyperlinkButton Content="Navigate to Page" NavigateUri="{Binding RowData.Id, Converter={StaticResource Conv}}" />
			</DataTemplate>
		</ig:UnboundColumn.ItemTemplate>
	</ig:UnboundColumn>
</ig:XamGrid.Columns>
...

I hope that this will help you.